DLMF:28.4#Ex5 (Q8194): Difference between revisions

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Property / constraint
 

A 2 ⁢ m + 1 = A 2 ⁢ m + 1 2 ⁢ n + 1 ⁢ ( q ) subscript 𝐴 2 𝑚 1 superscript subscript 𝐴 2 𝑚 1 2 𝑛 1 𝑞 {\displaystyle{\displaystyle A_{2m+1}=A_{2m+1}^{2n+1}(q)}}

A_{2m+1}=A_{2m+1}^{2n+1}(q)
Property / constraint: A 2 ⁢ m + 1 = A 2 ⁢ m + 1 2 ⁢ n + 1 ⁢ ( q ) subscript 𝐴 2 𝑚 1 superscript subscript 𝐴 2 𝑚 1 2 𝑛 1 𝑞 {\displaystyle{\displaystyle A_{2m+1}=A_{2m+1}^{2n+1}(q)}} / rank
 
Normal rank

Latest revision as of 17:23, 30 December 2019

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DLMF:28.4#Ex5
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    Statements

    test
    ( a - ( 2 ⁢ m + 1 ) 2 ) ⁢ A 2 ⁢ m + 1 - q ⁢ ( A 2 ⁢ m - 1 + A 2 ⁢ m + 3 ) = 0 𝑎 superscript 2 𝑚 1 2 subscript 𝐴 2 𝑚 1 𝑞 subscript 𝐴 2 𝑚 1 subscript 𝐴 2 𝑚 3 0 {\displaystyle{\displaystyle\left(a-(2m+1)^{2}\right)A_{2m+1}-q(A_{2m-1}+A_{2m% +3})=0}}
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    DLMF id
    DLMF:28.4#Ex5
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    comment
    Warning: Falling back to standard tex;
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    constraint
    a = a 2 ⁢ n + 1 ⁡ ( q ) 𝑎 Mathieu-eigenvalue-a 2 𝑛 1 𝑞 {\displaystyle{\displaystyle a=a_{2n+1}\left(q\right)}}
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    a = a 2 ⁢ n + 1 ⁢ ( q ) 𝑎 subscript 𝑎 2 𝑛 1 𝑞 {\displaystyle{\displaystyle a=a_{2n+1}\left(q\right)}}
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    A 2 ⁢ m + 1 = A 2 ⁢ m + 1 2 ⁢ n + 1 ⁢ ( q ) subscript 𝐴 2 𝑚 1 superscript subscript 𝐴 2 𝑚 1 2 𝑛 1 𝑞 {\displaystyle{\displaystyle A_{2m+1}=A_{2m+1}^{2n+1}(q)}}
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