DLMF:1.15.E52 (Q594)

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DLMF:1.15.E52
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    Statements

    D k I α = D n I α + n - k , superscript 𝐷 𝑘 superscript 𝐼 𝛼 superscript 𝐷 𝑛 superscript 𝐼 𝛼 𝑛 𝑘 {\displaystyle{\displaystyle D^{k}I^{\alpha}=D^{n}I^{\alpha+n-k},}}
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    Warning: Falling back to standard tex;
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    k = 1 , 2 , , n 𝑘 1 2 𝑛 {\displaystyle{\displaystyle k=1,2,\dots,n}}
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    k 𝑘 {\displaystyle{\displaystyle k}}
    C1.S1.XMD4.m1edec
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    n 𝑛 {\displaystyle{\displaystyle n}}
    C1.S1.XMD7.m1ydec
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    I α superscript 𝐼 𝛼 {\displaystyle{\displaystyle I^{\alpha}}}
    C1.S15.XMD12.m1ddec
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