DLMF:19.5.E11 (Q6140)

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DLMF:19.5.E11
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    k m + 1 = 1 - 1 - k m 2 1 + 1 - k m 2 , subscript 𝑘 𝑚 1 1 1 superscript subscript 𝑘 𝑚 2 1 1 superscript subscript 𝑘 𝑚 2 {\displaystyle{\displaystyle k_{m+1}=\frac{1-\sqrt{1-k_{m}^{2}}}{1+\sqrt{1-k_{% m}^{2}}},}}
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    Warning: Falling back to standard tex;
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