DLMF:24.6.E4 (Q7468)

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DLMF:24.6.E4
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    E 2 n = k = 1 n 1 2 k - 1 j = 1 k ( - 1 ) j ( 2 k k - j ) j 2 n , Euler-number-E 2 𝑛 superscript subscript 𝑘 1 𝑛 1 superscript 2 𝑘 1 superscript subscript 𝑗 1 𝑘 superscript 1 𝑗 binomial 2 𝑘 𝑘 𝑗 superscript 𝑗 2 𝑛 {\displaystyle{\displaystyle E_{2n}=\sum_{k=1}^{n}\frac{1}{2^{k-1}}\sum_{j=1}^% {k}(-1)^{j}{2k\choose k-j}j^{2n},}}
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