DLMF:25.6.E20 (Q7657)

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DLMF:25.6.E20
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    1 2 ( 2 2 n - 1 ) ζ ( 2 n ) = k = 1 n - 1 ( 2 2 n - 2 k - 1 ) ζ ( 2 n - 2 k ) ζ ( 2 k ) , 1 2 superscript 2 2 𝑛 1 Riemann-zeta 2 𝑛 superscript subscript 𝑘 1 𝑛 1 superscript 2 2 𝑛 2 𝑘 1 Riemann-zeta 2 𝑛 2 𝑘 Riemann-zeta 2 𝑘 {\displaystyle{\displaystyle\tfrac{1}{2}(2^{2n}-1)\zeta\left(2n\right)=\sum_{k% =1}^{n-1}(2^{2n-2k}-1)\zeta\left(2n-2k\right)\zeta\left(2k\right),}}
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