DLMF:26.8.E26 (Q7854)

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DLMF:26.8.E26
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    Statements

    test
    S ⁡ ( n + k + 1 , k ) = ∑ j = 0 k j ⁢ S ⁡ ( n + j , j ) . Stirling-number-second-kind-S 𝑛 𝑘 1 𝑘 superscript subscript 𝑗 0 𝑘 𝑗 Stirling-number-second-kind-S 𝑛 𝑗 𝑗 {\displaystyle{\displaystyle S\left(n+k+1,k\right)=\sum_{j=0}^{k}jS\left(n+j,j% \right).}}
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    DLMF id
    DLMF:26.8.E26
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