DLMF:4.6.E5 (Q1574)

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DLMF:4.6.E5
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    test
    ln ⁡ ( z + 1 z - 1 ) = 2 ⁢ ( 1 z + 1 3 ⁢ z 3 + 1 5 ⁢ z 5 + ⋯ ) , 𝑧 1 𝑧 1 2 1 𝑧 1 3 superscript 𝑧 3 1 5 superscript 𝑧 5 ⋯ {\displaystyle{\displaystyle\ln\left(\frac{z+1}{z-1}\right)=2\left(\frac{1}{z}% +\frac{1}{3z^{3}}+\frac{1}{5z^{5}}+\cdots\right),}}
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    DLMF id
    DLMF:4.6.E5
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