DLMF:6.5.E4 (Q2244)

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DLMF:6.5.E4
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    test
    1 2 ⁢ ( Ei ⁡ ( x ) - E 1 ⁡ ( x ) ) = Chi ⁡ ( x ) = Ci ⁡ ( i ⁢ x ) - 1 2 ⁢ π ⁢ i . 1 2 exponential-integral-Ei 𝑥 exponential-integral 𝑥 hyperbolic-cosine-integral 𝑥 cosine-integral 𝑖 𝑥 1 2 𝜋 𝑖 {\displaystyle{\displaystyle\tfrac{1}{2}(\mathrm{Ei}\left(x\right)-E_{1}\left(% x\right))=\mathrm{Chi}\left(x\right)=\mathrm{Ci}\left(ix\right)-\tfrac{1}{2}% \pi i.}}
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    DLMF:6.5.E4
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