DLMF:8.4.E6 (Q2500)

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DLMF:8.4.E6
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    test
    Γ ⁡ ( 1 2 , z 2 ) = 2 ⁢ ∫ z ∞ e - t 2 ⁢ d t = π ⁢ erfc ⁡ ( z ) . incomplete-Gamma 1 2 superscript 𝑧 2 2 superscript subscript 𝑧 superscript 𝑒 superscript 𝑡 2 𝑡 𝜋 complementary-error-function 𝑧 {\displaystyle{\displaystyle\Gamma\left(\tfrac{1}{2},z^{2}\right)=2\int_{z}^{% \infty}e^{-t^{2}}\mathrm{d}t=\sqrt{\pi}\operatorname{erfc}\left(z\right).}}
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    DLMF:8.4.E6
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