DLMF:10.41#Ex4 (Q3604)

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DLMF:10.41#Ex4
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    U 2 ( p ) = 1 1152 ( 81 p 2 - 462 p 4 + 385 p 6 ) , subscript 𝑈 2 𝑝 1 1152 81 superscript 𝑝 2 462 superscript 𝑝 4 385 superscript 𝑝 6 {\displaystyle{\displaystyle U_{2}(p)=\tfrac{1}{1152}(81p^{2}-462p^{4}+385p^{6% }),}}
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    Warning: Falling back to standard tex;
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