DLMF:11.6#Ex3 (Q3986)

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DLMF:11.6#Ex3
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    c 2 ( λ ) = 6 λ - 4 - 1 2 λ - 2 , subscript 𝑐 2 𝜆 6 superscript 𝜆 4 1 2 superscript 𝜆 2 {\displaystyle{\displaystyle c_{2}(\lambda)=6\lambda^{-4}-\tfrac{1}{2}\lambda^% {-2},}}
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    Warning: Falling back to standard tex;
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