DLMF:11.11#Ex6 (Q4078)

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DLMF:11.11#Ex6
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    test
    b 1 ⁢ ( λ ) = 2 + 3 ⁢ λ 2 12 ⁢ ( 1 - λ 2 ) 7 / 4 , subscript 𝑏 1 𝜆 2 3 superscript 𝜆 2 12 superscript 1 superscript 𝜆 2 7 4 {\displaystyle{\displaystyle b_{1}(\lambda)=\frac{2+3\lambda^{2}}{12(1-\lambda% ^{2})^{7/4}},}}
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    DLMF:11.11#Ex6
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    comment
    Warning: Falling back to standard tex;
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