DLMF:14.5.E16 (Q4728)

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DLMF:14.5.E16
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    test
    P ν - 1 / 2 ⁡ ( cosh ⁡ ξ ) = ( 2 π ⁢ sinh ⁡ ξ ) 1 / 2 ⁢ sinh ⁡ ( ( ν + 1 2 ) ⁢ ξ ) ν + 1 2 , Legendre-P-first-kind 1 2 𝜈 𝜉 superscript 2 𝜋 𝜉 1 2 𝜈 1 2 𝜉 𝜈 1 2 {\displaystyle{\displaystyle P^{-1/2}_{\nu}\left(\cosh\xi\right)=\left(\frac{2% }{\pi\sinh\xi}\right)^{1/2}\frac{\sinh\left(\left(\nu+\frac{1}{2}\right)\xi% \right)}{\nu+\frac{1}{2}},}}
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    DLMF:14.5.E16
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