DLMF:14.15.E5 (Q4851)

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DLMF:14.15.E5
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    α = ν + 1 2 μ ( < 1 ) , 𝛼 annotated 𝜈 1 2 𝜇 absent 1 {\displaystyle{\displaystyle\alpha=\frac{\nu+\frac{1}{2}}{\mu}\,(<1),}}
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    Warning: Falling back to standard tex;
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    μ 𝜇 {\displaystyle{\displaystyle\mu}}
    C14.S1.XMD7.m1ddec
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    ν 𝜈 {\displaystyle{\displaystyle\nu}}
    C14.S1.XMD8.m1ddec
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    α 𝛼 {\displaystyle{\displaystyle\alpha}}
    C14.S15.XMD3.m1adec
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