DLMF:14.15.E19 (Q4865)

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DLMF:14.15.E19
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    α = μ ν + 1 2 ( < 1 ) , 𝛼 annotated 𝜇 𝜈 1 2 absent 1 {\displaystyle{\displaystyle\alpha=\frac{\mu}{\nu+\frac{1}{2}}\,(<1),}}
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    Warning: Falling back to standard tex;
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    μ 𝜇 {\displaystyle{\displaystyle\mu}}
    C14.S1.XMD7.m1odec
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