DLMF:15.4.E26 (Q5010)

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DLMF:15.4.E26
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    Statements

    test
    F ⁡ ( a , b ; a - b + 1 ; - 1 ) = Γ ⁡ ( a - b + 1 ) ⁢ Γ ⁡ ( 1 2 ⁢ a + 1 ) Γ ⁡ ( a + 1 ) ⁢ Γ ⁡ ( 1 2 ⁢ a - b + 1 ) . Gauss-hypergeometric-F 𝑎 𝑏 𝑎 𝑏 1 1 Euler-Gamma 𝑎 𝑏 1 Euler-Gamma 1 2 𝑎 1 Euler-Gamma 𝑎 1 Euler-Gamma 1 2 𝑎 𝑏 1 {\displaystyle{\displaystyle F\left(a,b;a-b+1;-1\right)=\frac{\Gamma\left(a-b+% 1\right)\Gamma\left(\tfrac{1}{2}a+1\right)}{\Gamma\left(a+1\right)\Gamma\left(% \tfrac{1}{2}a-b+1\right)}.}}
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    DLMF id
    DLMF:15.4.E26
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