DLMF:18.2#Ex5 (Q5503)

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DLMF:18.2#Ex5
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    test
    b n = k ~ n k n - k ~ n + 1 k n + 1 = h ~ n h n , subscript 𝑏 𝑛 subscript ~ 𝑘 𝑛 subscript 𝑘 𝑛 subscript ~ 𝑘 𝑛 1 subscript 𝑘 𝑛 1 subscript ~ ℎ 𝑛 subscript ℎ 𝑛 {\displaystyle{\displaystyle b_{n}=\frac{\tilde{k}_{n}}{k_{n}}-\frac{\tilde{k}% _{n+1}}{k_{n+1}}=\frac{\tilde{h}_{n}}{h_{n}},}}
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    DLMF:18.2#Ex5
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    comment
    Warning: Falling back to standard tex;
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