DLMF:1.15.E52 (Q594)

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DLMF:1.15.E52
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    D k I α = D n I α + n - k , superscript 𝐷 𝑘 superscript 𝐼 𝛼 superscript 𝐷 𝑛 superscript 𝐼 𝛼 𝑛 𝑘 {\displaystyle{\displaystyle D^{k}I^{\alpha}=D^{n}I^{\alpha+n-k},}}
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    Warning: Falling back to standard tex;
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