DLMF:18.15#Ex6 (Q5710)

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DLMF:18.15#Ex6
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    test
    b 1 ⁢ ( x ) = 1 48 ⁢ x 1 2 ⁢ ( 4 ⁢ x 2 - 12 ⁢ α 2 - 24 ⁢ α ⁢ x - 24 ⁢ x + 3 ) . subscript 𝑏 1 𝑥 1 48 superscript 𝑥 1 2 4 superscript 𝑥 2 12 superscript 𝛼 2 24 𝛼 𝑥 24 𝑥 3 {\displaystyle{\displaystyle b_{1}(x)=\frac{1}{48x^{\frac{1}{2}}}\left(4x^{2}-% 12\alpha^{2}-24\alpha x-24x+3\right).}}
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    DLMF:18.15#Ex6
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    Warning: Falling back to standard tex;
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