DLMF:19.7#Ex18 (Q6199)

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DLMF:19.7#Ex18
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    test
    α 1 2 = α 2 + k 2 1 + k 2 . superscript subscript 𝛼 1 2 superscript 𝛼 2 superscript 𝑘 2 1 superscript 𝑘 2 {\displaystyle{\displaystyle\alpha_{1}^{2}=\frac{\alpha^{2}+k^{2}}{1+k^{2}}.}}
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    DLMF:19.7#Ex18
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    comment
    Warning: Falling back to standard tex;
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