DLMF:19.8.E3 (Q6209)

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DLMF:19.8.E3
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    Statements

    test
    c n + 1 = a n - g n 2 = c n 2 4 ⁢ a n + 1 , subscript 𝑐 𝑛 1 subscript 𝑎 𝑛 subscript 𝑔 𝑛 2 superscript subscript 𝑐 𝑛 2 4 subscript 𝑎 𝑛 1 {\displaystyle{\displaystyle c_{n+1}=\frac{a_{n}-g_{n}}{2}=\frac{c_{n}^{2}}{4a% _{n+1}},}}
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    DLMF id
    DLMF:19.8.E3
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    comment
    Warning: Falling back to standard tex;
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