DLMF:19.8#Ex5 (Q6216)

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DLMF:19.8#Ex5
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    test
    Q n + 1 = 1 2 ⁢ Q n ⁢ ε n subscript 𝑄 𝑛 1 1 2 subscript 𝑄 𝑛 subscript 𝜀 𝑛 {\displaystyle{\displaystyle Q_{n+1}=\tfrac{1}{2}Q_{n}\varepsilon_{n}}}
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    DLMF:19.8#Ex5
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    Warning: Falling back to standard tex;
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