DLMF:19.14.E5 (Q6310)

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DLMF:19.14.E5
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    sin 2 ϕ = γ - α U 2 + γ , 2 italic-ϕ 𝛾 𝛼 superscript 𝑈 2 𝛾 {\displaystyle{\displaystyle{\sin^{2}}\phi=\frac{\gamma-\alpha}{U^{2}+\gamma},}}
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