DLMF:19.34.E3 (Q6715)

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DLMF:19.34.E3
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    test
    2 ⁢ a ⁢ b ⁢ I ⁢ ( 𝐞 5 ) = a 3 ⁢ I ⁢ ( 𝟎 ) - I ⁢ ( 𝐞 3 ) = a 3 ⁢ I ⁢ ( 𝟎 ) - r + 2 ⁢ r - 2 ⁢ I ⁢ ( - 𝐞 3 ) = 2 ⁢ a ⁢ b ⁢ ( I ⁢ ( 𝟎 ) - r - 2 ⁢ I ⁢ ( 𝐞 1 - 𝐞 3 ) ) , 2 𝑎 𝑏 𝐼 subscript 𝐞 5 subscript 𝑎 3 𝐼 0 𝐼 subscript 𝐞 3 subscript 𝑎 3 𝐼 0 superscript subscript 𝑟 2 superscript subscript 𝑟 2 𝐼 subscript 𝐞 3 2 𝑎 𝑏 𝐼 0 superscript subscript 𝑟 2 𝐼 subscript 𝐞 1 subscript 𝐞 3 {\displaystyle{\displaystyle 2abI(\mathbf{e}_{5})=a_{3}I(\boldsymbol{{0}})-I(% \mathbf{e}_{3})=a_{3}I(\boldsymbol{{0}})-r_{+}^{2}r_{-}^{2}I(-\mathbf{e}_{3})=% 2ab(I(\boldsymbol{{0}})-r_{-}^{2}I(\mathbf{e}_{1}-\mathbf{e}_{3})),}}
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    DLMF:19.34.E3
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    Warning: Falling back to standard tex;
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