DLMF:22.6.E18 (Q6952)

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DLMF:22.6.E18
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    test
    1 - dn ⁡ ( 2 ⁢ z , k ) 1 + dn ⁡ ( 2 ⁢ z , k ) = k 2 ⁢ sn 2 ⁡ ( z , k ) ⁢ cn 2 ⁡ ( z , k ) dn 2 ⁡ ( z , k ) . 1 Jacobi-elliptic-dn 2 𝑧 𝑘 1 Jacobi-elliptic-dn 2 𝑧 𝑘 superscript 𝑘 2 Jacobi-elliptic-sn 2 𝑧 𝑘 Jacobi-elliptic-cn 2 𝑧 𝑘 Jacobi-elliptic-dn 2 𝑧 𝑘 {\displaystyle{\displaystyle\frac{1-\operatorname{dn}\left(2z,k\right)}{1+% \operatorname{dn}\left(2z,k\right)}=\frac{k^{2}{\operatorname{sn}^{2}}\left(z,% k\right){\operatorname{cn}^{2}}\left(z,k\right)}{{\operatorname{dn}^{2}}\left(% z,k\right)}.}}
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    DLMF id
    DLMF:22.6.E18
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