DLMF:26.15.E11 (Q7978)

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DLMF:26.15.E11
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    test
    ∑ k = 0 n r n - k ⁢ ( B ) ⁢ ( x - k + 1 ) k = ∏ j = 1 n ( x + b j - j + 1 ) . superscript subscript 𝑘 0 𝑛 subscript 𝑟 𝑛 𝑘 𝐵 subscript 𝑥 𝑘 1 𝑘 superscript subscript product 𝑗 1 𝑛 𝑥 subscript 𝑏 𝑗 𝑗 1 {\displaystyle{\displaystyle\sum_{k=0}^{n}r_{n-k}(B)(x-k+1)_{k}=\prod_{j=1}^{n% }(x+b_{j}-j+1).}}
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    DLMF id
    DLMF:26.15.E11
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    comment
    Warning: Falling back to standard tex;
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