DLMF:31.8#Ex6 (Q9040)

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DLMF:31.8#Ex6
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    ν 2 = ( λ + a + 1 ) ( λ 2 - 4 a ) superscript 𝜈 2 𝜆 𝑎 1 superscript 𝜆 2 4 𝑎 {\displaystyle{\displaystyle\nu^{2}=(\lambda+a+1)(\lambda^{2}-4a)}}
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    Warning: Falling back to standard tex;
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