Orthogonal Polynomials - 18.30 Associated OP’s
DLMF | Formula | Constraints | Maple | Mathematica | Symbolic Maple |
Symbolic Mathematica |
Numeric Maple |
Numeric Mathematica |
---|---|---|---|---|---|---|---|---|
18.30.E1 | Failed to parse (LaTeXML (experimental; uses MathML): Invalid response ("") from server "http://latexml:8080/convert/":): {\displaystyle A_{n}A_{n+1}C_{n+1} > 0}
A_{n}A_{n+1}C_{n+1} > 0 |
Failed to parse (LaTeXML (experimental; uses MathML): Invalid response ("") from server "http://latexml:8080/convert/":): {\displaystyle n \geq 0} | A[n]*A[n + 1]*C[n + 1] > 0 |
Subscript[A, n]*Subscript[A, n + 1]*Subscript[C, n + 1] > 0 |
Skipped - no semantic math | Skipped - no semantic math | - | - |
18.30#Ex1 | Failed to parse (LaTeXML (experimental; uses MathML): Invalid response ("") from server "http://latexml:8080/convert/":): {\displaystyle p_{-1}(x;c) = 0}
p_{-1}(x;c) = 0 |
Failed to parse (LaTeXML (experimental; uses MathML): Invalid response ("") from server "http://latexml:8080/convert/":): {\displaystyle } | p[- 1](x ; c) = 0 |
Subscript[p, - 1][x ; c] == 0 |
Skipped - no semantic math | Skipped - no semantic math | - | - |
18.30#Ex2 | Failed to parse (LaTeXML (experimental; uses MathML): Invalid response ("") from server "http://latexml:8080/convert/":): {\displaystyle p_{0}(x;c) = 1}
p_{0}(x;c) = 1 |
Failed to parse (LaTeXML (experimental; uses MathML): Invalid response ("") from server "http://latexml:8080/convert/":): {\displaystyle } | p[0](x ; c) = 1 |
Subscript[p, 0][x ; c] == 1 |
Skipped - no semantic math | Skipped - no semantic math | - | - |
18.30.E3 | Failed to parse (LaTeXML (experimental; uses MathML): Invalid response ("") from server "http://latexml:8080/convert/":): {\displaystyle p_{n+1}(x;c) = (A_{n+c}x+B_{n+c})p_{n}(x;c)-C_{n+c}p_{n-1}(x;c)}
p_{n+1}(x;c) = (A_{n+c}x+B_{n+c})p_{n}(x;c)-C_{n+c}p_{n-1}(x;c) |
Failed to parse (LaTeXML (experimental; uses MathML): Invalid response ("") from server "http://latexml:8080/convert/":): {\displaystyle } | p[n + 1](x ; c) = (A[n + c]*x + B[n + c])*p[n](x ; c)- C[n + c]*p[n - 1](x ; c) |
Subscript[p, n + 1][x ; c] == (Subscript[A, n + c]*x + Subscript[B, n + c])*Subscript[p, n][x ; c]- Subscript[C, n + c]*Subscript[p, n - 1][x ; c] |
Skipped - no semantic math | Skipped - no semantic math | - | - |