DLMF:4.4.E19 (Q1553)

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DLMF:4.4.E19
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    test
    lim n → ∞ ⁡ ( ( ∑ k = 1 n 1 k ) - ln ⁡ n ) = γ = 0.57721 56649 01532 86060 ⁢ … , subscript → 𝑛 subscript superscript 𝑛 𝑘 1 1 𝑘 𝑛 0.57721 56649 01532 86060 … {\displaystyle{\displaystyle\lim_{n\to\infty}\left(\left(\sum^{n}_{k=1}\frac{1% }{k}\right)-\ln n\right)=\gamma=0.57721\ 56649\ 01532\ 86060\dots,}}
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    DLMF id
    DLMF:4.4.E19
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