DLMF:4.12.E6 (Q1634)

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DLMF:4.12.E6
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    Statements

    test
    ϕ ⁢ ( x ) = ln ⁡ ( x + 1 ) , italic-ϕ 𝑥 𝑥 1 {\displaystyle{\displaystyle\phi(x)=\ln\left(x+1\right),}}
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    DLMF id
    DLMF:4.12.E6
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    constraint
    - 1 < x < 0 1 𝑥 0 {\displaystyle{\displaystyle-1<x<0}}
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