DLMF:15.10#Ex4 (Q5119)

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DLMF:15.10#Ex4
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    f 2 ( z ) = ( 1 - z ) c - a - b F ( c - a , c - b c - a - b + 1 ; 1 - z ) , subscript 𝑓 2 𝑧 superscript 1 𝑧 𝑐 𝑎 𝑏 Gauss-hypergeometric-F 𝑐 𝑎 𝑐 𝑏 𝑐 𝑎 𝑏 1 1 𝑧 {\displaystyle{\displaystyle f_{2}(z)=(1-z)^{c-a-b}F\left({c-a,c-b\atop c-a-b+% 1};1-z\right),}}
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