DLMF:3.9.E12 (Q1399)

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DLMF:3.9.E12
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    s n = j = 1 n ( - 1 ) j + 1 j 2 , subscript 𝑠 𝑛 superscript subscript 𝑗 1 𝑛 superscript 1 𝑗 1 superscript 𝑗 2 {\displaystyle{\displaystyle s_{n}=\sum_{j=1}^{n}\frac{(-1)^{j+1}}{j^{2}},}}
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    Warning: Falling back to standard tex;
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    s n subscript 𝑠 𝑛 {\displaystyle{\displaystyle s_{n}}}
    C3.S9.XMD1.m1edec
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