DLMF:5.4#Ex6 (Q2051)

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DLMF:5.4#Ex6
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    ψ ′ ⁡ ( 1 2 ) = 1 2 ⁢ π 2 . diffop digamma 1 1 2 1 2 superscript 𝜋 2 {\displaystyle{\displaystyle\psi'\left(\tfrac{1}{2}\right)=\tfrac{1}{2}\pi^{2}% .}}
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    DLMF:5.4#Ex6
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