DLMF:11.6#Ex5 (Q3988)

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DLMF:11.6#Ex5
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    c 4 ( λ ) = 70 λ - 8 - 45 2 λ - 6 + 3 8 λ - 4 . subscript 𝑐 4 𝜆 70 superscript 𝜆 8 45 2 superscript 𝜆 6 3 8 superscript 𝜆 4 {\displaystyle{\displaystyle c_{4}(\lambda)=70\lambda^{-8}-\tfrac{45}{2}% \lambda^{-6}+\tfrac{3}{8}\lambda^{-4}.}}
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