DLMF:12.10#Ex19 (Q4199)

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DLMF:12.10#Ex19
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    𝖠 2 ( τ ) = 1 288 τ 2 ( 6160 τ 4 + 18480 τ 3 + 19404 τ 2 + 8028 τ + 945 ) . subscript 𝖠 2 𝜏 1 288 superscript 𝜏 2 6160 superscript 𝜏 4 18480 superscript 𝜏 3 19404 superscript 𝜏 2 8028 𝜏 945 {\displaystyle{\displaystyle\mathsf{A}_{2}(\tau)=\tfrac{1}{288}\tau^{2}(6160% \tau^{4}+18480\tau^{3}+19404\tau^{2}+8028\tau+945).}}
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