DLMF:28.4#Ex12 (Q8205)

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DLMF:28.4#Ex12
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    A 2 n + 1 2 n + 1 ( 0 ) = 1 , subscript superscript 𝐴 2 𝑛 1 2 𝑛 1 0 1 {\displaystyle{\displaystyle A^{2n+1}_{2n+1}(0)=1,}}
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