DLMF:28.31#Ex6 (Q8519)

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DLMF:28.31#Ex6
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    p ξ A 0 + ( 4 - η ) A 2 + ( 1 2 p + 2 ) ξ A 4 = 0 , 𝑝 𝜉 subscript 𝐴 0 4 𝜂 subscript 𝐴 2 1 2 𝑝 2 𝜉 subscript 𝐴 4 0 {\displaystyle{\displaystyle p\xi A_{0}+(4-\eta)A_{2}+\left(\tfrac{1}{2}p+2% \right)\xi A_{4}=0,}}
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