DLMF:30.16#Ex10 (Q8971)

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DLMF:30.16#Ex10
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    A j , j + 1 = - γ 2 ( 2 m + 2 j ) ( 2 m + 2 j + 1 ) ( 2 m + 4 j + 1 ) ( 2 m + 4 j + 3 ) , subscript 𝐴 𝑗 𝑗 1 superscript 𝛾 2 2 𝑚 2 𝑗 2 𝑚 2 𝑗 1 2 𝑚 4 𝑗 1 2 𝑚 4 𝑗 3 {\displaystyle{\displaystyle A_{j,j+1}=-\gamma^{2}\frac{(2m+2j)(2m+2j+1)}{(2m+% 4j+1)(2m+4j+3)},}}
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