DLMF:32.7#Ex4 (Q9291)

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DLMF:32.7#Ex4
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    β 3 = β 4 = β 0 - 2 . subscript 𝛽 3 subscript 𝛽 4 subscript 𝛽 0 2 {\displaystyle{\displaystyle\beta_{3}=\beta_{4}=\beta_{0}-2.}}
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